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x^2-6x-0.6=0
a = 1; b = -6; c = -0.6;
Δ = b2-4ac
Δ = -62-4·1·(-0.6)
Δ = 38.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{38.4}}{2*1}=\frac{6-\sqrt{38.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{38.4}}{2*1}=\frac{6+\sqrt{38.4}}{2} $
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